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3 years ago

35 birds to 45 birds?

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

6 0

I'm not sure what your trying to ask is that the full question

krok68 [10]3 years ago

3 0

There is a difference of 10

You might be interested in

the denominator of a fraction is 3 less than the numerator. If 5 is added to the numerator and denominator, the result is 5/6. F

Vitek1552 [10]

X=numerator
y=denominator
the sum of numerator and denominator=x+y
we suggest this system of equations:

y=x-3
(x+5) / (y+5)=5/6

we solve this system of equation by substitution method.
(x+5) / (x-3+5)=5/6
(x+5) / (x+2)=5/6
6(x+5)=5(x+2)
6x+30=5x+10
6x-5x=10-30
x=-20

y=x-3=-20-3=-23

Teh sum of the numerator an denominator=-20+(-23)=-43

Answer: -43

7 0

3 years ago

What is 2x3y if x = -2y =4

Lilit [14]

Answer:

-48

Step-by-step explanation:

2x3y

2(-2) * 3(4)

-4 * 12

-48

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

4 0

2 years ago

Read 2 more answers

Y= (x-9) (x+3)

juin [17]

Answer:

y = x² − 6x − 27

Step-by-step explanation:

To distribute, you can use something called FOIL. It stands for First, Outer, Inner, Last.

First, multiply the First term in each factor.

x · x = x²

Now multiply the Outer terms in each factor.

x · 3 = 3x

Next multiply the Inner terms in each factor.

-9 · x = -9x

Finally, multiply the Last terms in each factor.

-9 · 3 = -27

Add them all up:

x² + 3x − 9x − 27

x² − 6x − 27

4 0

3 years ago

Given: AABC, m_ACB=90°,<br> CD 1 AB, m ZACD=60º,<br> BC = 6 cm<br> Find: CD, Area of AABC

just olya [345]

Answer:

Look below

Step-by-step explanation:

Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.

This means triangle BCD is a 30-60-90 (angle measures) right triangle

The proportions of the sides (from smallest to largest) is

x:x√3:2x

We are given that BC = 6 cm. This means...

2x=6

x=3

This means DB is 3 cm and CD is 3√3 cm

Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.

x=3√3

x√3=9

2x=6√3

Now we need to find AB

AB = AD + DB

AB = 9 + 3

AB = 12 cm

$Area = \frac{1}{2} bh = \frac{1}{2}(12)(3\sqrt3)=6(3\sqrt3)=18\sqrt3$

8 0

2 years ago

The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

5 0

3 years ago