You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence
Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.
Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)
After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences
The confidence interval is in the form (L, U)
L = lower bound
L = dbar - t*sd/sqrt(n)
U = upper bound
U = dbar + t*sd/sqrt(n)
Answer: x² + 4x - 32
Step-by-step explanation: So to multiply these two binomials together, let's use the F.O.I.L. method.
Remember, F.O.I.L. stands for First, Outter, Inner, Last.
This is because we start with the product of the first terms which is x², then we add the product of the outer terms which is 8x, then we add the middle terms which is -4x, and then we add the product of the last terms which is -32.
So we have x² + 8x + -4x + -32.
Combining the like terms 8x + -4x, our final answer is x² + 4x - 32.
Answer:
9
Step-by-step explanation:
3x3 =9 hope this helps bbs
Answer:
The volume of the container is<u><em> 480</em></u> in.
Step-by-step explanation:
First, lets break the container into two figures, just to make it easier to calculate the volume or area.
The first figure is has the height of 10 in, length of 8 in, and width of 5 in.
10 × 8 × 5
10 × 8 = 80
80 × 5 = 400
The volume of the first figure is <em>400</em> in.
Next, lets calculate the volume of the second figure which has the height of 5 in, length of 4 in, and the width of also 4 in.
5 × 4 × 4
5 × 4 = 20
20 × 4 = 80
The volume of the second figure is <em>80 </em>in.
Now, lets add the volumes of the two figures to find the total volume, 400 in for the first figure, and 80 in for the second figure. v
400 + 80 = 480
The total volume of the figure is<u><em> 480 </em></u>in.
