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3 years ago

Solve for X!! Will mark brainliest

Mathematics

1 answer:

bekas [8.4K]3 years ago

4 0

Answer:

x=43 (being vertically opposite angles

Step-by-step explanation:

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Opposite of 8=? Brainliest

stich3 [128]

Answer:

-8

Step-by-step explanation:

The opposite of 8 is -8.

6 0

3 years ago

How to solve this trig

n200080 [17]

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

$\displaystyle \large{ cos \theta = - \frac{1}{2} }$

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

$\displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }$

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }$

Both values are apart of the interval. Hence,

$\displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }$

Second Question

Isolate sin(4 theta).

$\displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }$

Rationalize the denominator.

$\displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }$

The problem here is 4 beside theta. What we are going to do is to expand the interval.

$\displaystyle \large{0 \leqslant \theta < 2 \pi}$

Multiply whole by 4.

$\displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}$

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }$

Find Q4

$\displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }$

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

$\displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}$

Hence:-

For Q3

$\displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }$

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

$\displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }$

Therefore:-

$\displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }$

Then we divide all these values by 4.

$\displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }$

Let me know if you have any questions!

3 0

3 years ago

How do I solve 1/10x+5=-3x-13+4x ?

Temka [501]

Answer:

x = 20

I am not sure if you wanted the answer. Sorry!

Step-by-step explanation:

Let's solve your equation step-by-step.

1/10 x + 5 = - 3x - 13 + 4x

Step 1: Simplify both sides of the equation.

1/10 x + 5 = - 3x - 13 + 4x

1/10 x + 5 = - 3x + - 13 + 4x

1/10 x + 5 = (- 3x + 4x) + (- 13)

1/10 x + 5 = x + - 13

1/10 x + 5 = x - 13

Step 2: Subtract x from both sides.

1/10 x + 5 - x = x - 13 - x

- 9/10 x + 5 = - 13

Step 3: Subtract 5 from both sides

- 9/10 x + 5 - 5 = - 13 - 5

- 9/10 x = - 18

Step 4: Multiply both sides by 10/(- 9).

(10/ - 9) * (- 9/10 x) = (01/ - 9) * (- 18)

x = 20

Hope this helps!

4 0

3 years ago

Read 2 more answers

Can someone solve this??

Dima020 [189]

Answer:

see below

Step-by-step explanation:

There are a few relevant relations involved:

an inscribed angle is half the measure of the arc it intercepts
an arc has the same measure as the central angle that intercepts it
the angle exterior to a circle where secants meet is half the difference of the intercepted arcs (near and far)
the angle interior to a circle where secants meet is half the sum of the intercepted arcs
the angle where tangents meet is the supplement of the (near) arc intercepted
an exterior angle of a triangle is equal to the sum of the remote interior angles
the angle between a tangent and a radius is 90°
the angle sum theorem

AB is a diameter, so arcs AB are 180°.

a) BC is the supplement to arc AC: 180° -140° = 40°

b) BG is the supplement to AG: 180° -64° -38° = 78°

c) ∠1 has the measure of BC: 40°

d) ∠2 is inscribed in a semicircle, so has measure 180°/2 = 90°

e) ∠3 is half the measure of arc AE: 64°/2 = 32°

f) ∠4 is half the sum of arcs AG and BC: ((64°+38°) +40°)/2 = 71°

g) ∠5 is half the difference of arcs AC and EG: (140° -38°)/2 = 51°

h) ∠6 is half the sum of arcs EAC and BG: ((140°+64°) +78°)/2 = 141°

i) ∠7 is the difference of exterior angle 4 and interior angle 1: 71° -40° = 31°

j) ∠8 is the measure of arc AC: 140°

k) ∠9 is the supplement to arc AC: 180° -140° = 40°

l) ∠10 is the complement of angle 7: 90° -31° = 59°

3 0

3 years ago

The critical points of a rational inequality are -1, 3, and 4. Which set of points can be tested to find a complete solution

mars1129 [50]

Answer:

It would be D. I got it correct on Edgenuity.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers