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CaHeK987 [17]
2 years ago
8

X-Y-2Z =-11 X-2Y-Z = -11 -X+Y+3Z = 14

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

9514 1404 393

Answer:

  (X, Y, Z) = (-2, 3, 3)

Step-by-step explanation:

We can subtract the second equation from the first to get ...

  Y -Z = 0

We can add the third equation to the first to get ...

  Z = 3

Then ...

  Y -3 = 0   ⇒   Y = 3

and ...

  X -3 -2(3) = -11

  X = -2 . . . . . . . . . add 9

The solution is ...

  (X, Y, Z) = (-2, 3, 3)

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Answer:

Option B. Cosec θ = –5/3

Option C. Cot θ = 4/3

Option D. Cos θ = –4/5

Step-by-step explanation:

From the question given above, the following data were obtained:

Tan θ = 3/4

θ is in 3rd quadrant

Recall

Tan θ = Opposite / Adjacent

Tan θ = 3/4 = Opposite / Adjacent

Thus,

Opposite = 3

Adjacent = 4

Next, we shall determine the Hypothenus. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus =?

Hypo² = Opp² + Adj²

Hypo² = 3² + 4²

Hypo² = 9 + 16

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Take the square root of both side

Hypo = √25

Hypothenus = 5

Recall:

In the 3rd quadant, only Tan is positive.

Therefore,

Hypothenus = –5

Finally, we shall determine Sine θ, Cos θ, Cot θ and Cosec θ to determine which option is correct. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus = –5

Sine θ = Opposite / Hypothenus

Sine θ = 3/–5

Sine θ = –3/5

Cos θ = Adjacent / Hypothenus

Cos θ = 4/–5

Cos θ = –4/5

Cot θ = 1/ Tan θ

Tan θ = 3/4

Cot θ = 1 ÷ 3/4

Invert

Cot θ = 1 × 4/3

Cot θ = 4/3

Cosec θ = 1/ Sine θ

Sine θ = –3/5

Cosec θ = 1 ÷ –3/5

Invert

Cosec θ = 1 × –5/3

Cosec θ = –5/3

SUMMARY

Sine θ = –3/5

Cos θ = –4/5

Tan θ = 3/4

Cot θ = 4/3

Cosec θ = –5/3

Therefore, option B, C and D gives the correct answer to the question.

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