Copper(ii)nitrate is the name
Explanation:
34.2g of C12H22O11 is dissolved in 180g of H20.
Molar mass of sucrose = 342g/mol
Moles of sucrose = 342 / 34.2 = 10 mol.
Molar mass of water = 18g/mol
Moles of water = 180 / 18 = 10 mol.
For hydrogen atoms, there are 22 * 10 in sucrose and 2 * 10 in water, which gives a total of 240.
For oxygen atoms, there are 11 * 10 in sucrose and 1 * 10 in water, which gives a total of 120.
Your going to want to round 8.01 to 8.01 and change 3.127 rounded too 3.1
then u want to take 8.0 and 3.1 and times it and u will get 24.8 or 25
The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.
The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H
1) H2 in SrH2
Sr atomic mass = 87.62 g/mol
H2 molar mass = 2.02 g/mol
Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol
Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2
Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2
=> x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2
2) H2 in H2O
2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2
3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g
Answer: 0.575 g
