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Mariana [72]
3 years ago
8

You wish to calculate the mass of hydrogen gas that can be prepared from 4.93 g of srh2 and 4.14 g of h2o.

Chemistry
1 answer:
Ivenika [448]3 years ago
7 0
The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.

The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H

1) H2 in SrH2

Sr atomic mass = 87.62 g/mol

H2 molar mass = 2.02 g/mol

Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol

Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2

Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2

=> x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2

2) H2 in H2O

2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2

3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g

Answer: 0.575 g
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How may moles are in 19L of oxygen gas?
skad [1K]

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0.85\,\,mole

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Solution:

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Arrange these 3 reactions according to increasing DS. (1) CH4(g) H2O(g) --> CO(g) 3 H2(g) (2) C(s) O2(g) --> CO2(g) (3) H2
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Answer:

1 < 3 < 2.

Explanation:

Entropy is the measurement of the degree of disorderliness in a system. The term ''entropy" is one of the important aspect in kinetics and thermodynamics. Entropy is designated with the alphabet symbol "S" and a change in entropy is ∆S.

The main idea in order to solve this question is very simple. Let us make reference to your clothes that you wear. At first, your clothes when you wear them, they are neat and clean but as time goes by the clothes will get dirty, this is a layman example of entropy.

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But in this reaction the number of moles of the products has decreased.

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