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andreev551 [17]
3 years ago
12

Graph function g f(x)=(x-1)^2-5 g(x)=f(x+2)

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0

9514 1404 393

Answer:

  C  (see below)

Step-by-step explanation:

The function f(x) is written in vertex form:

  f(x) = a(x -h)^2 +k . . . . . scale factor 'a', vertex (h, k)

The vertex of function f(x) is (1, -5).

The function g(x) = f(x +2) represents a shift left by 2 units. When the vertex of f(x) is shifted left 2 units, it becomes (1-2, -5) = (-1, -5).

The graph with the vertex in this location is the third problem attachment, shown below.

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think of it as a fraction

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Which of the following could not be the graph of a function of X?
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D

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Please help this is my 3rd time asking :(​
Ainat [17]

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$6

Step-by-step explanation:

She bought a toy for 4 dollars, so we need to subtract that from 88. This gives us 84 dolalrs. She bought 8 shirts and 6 pants, which is 14 items total. Divide 88 by 14 and you get 6.

Hope that helps :)

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A research analyst for a car rental agency found that the probability distribution function for the age of the rental car (in ye
alexdok [17]

Answer:

10 years

Step-by-step explanation:

Given

Decline from (0,h) to (10,0)

See attachment for graph

Required

Determine the age when height = 0

The function of the graph is represented as: (age, height)

So, we need to read from the graph the corresponding value of age (on the x-axis) when height = 0 (i.e. the y-axis)

From the attached graph;

age = 10 when height = 0

<em>Hence, the age of the car is 10 years</em>

4 0
3 years ago
Solve for x<br><img src="https://tex.z-dn.net/?f=0%20%3D%20%20-%20%7B%20e%20%7D%5E%7B%20-%20x%7D%20%20%2B%203%20%7Be%7D%5E%7B3x%
Brilliant_brown [7]

\bf \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{log_a a^x = x}\qquad \qquad a^{log_a x}=x~\hfill\stackrel{recall}{ln=log_e}\qquad log_e(e^z)=z \\\\[-0.35em] \rule{34em}{0.25pt}


\bf 0=-e^{-x}+3e^{3x}\implies e^{-x}=3e^{3x}\implies \cfrac{1}{e^x}=3e^{3x}\implies 1=e^x\cdot 3e^{3x} \\\\\\ 1=3e^xe^{3x}\implies \cfrac{1}{3}=e^{x+3x}\implies \cfrac{1}{3}=e^{4x}\implies ln\left( \cfrac{1}{3} \right)=ln\left( e^{4x} \right) \\\\\\ ln\left( \cfrac{1}{3} \right)=4x\implies \cfrac{ln\left( \frac{1}{3} \right)}{4}=x


and you plug that in your calculator to get about -0.27465307216702742285.

8 0
3 years ago
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