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VladimirAG [237]

3 years ago

9

A problem states: "There are 5 more girls than boys at the party. There are 27 children at the party in all. How many boys are t

here at the party?"
Let b represent the number of boys

Which expression represents the number of girls?

A: b - 5
B: b + 5
C: 5 - b
D: b · 5

1 answer:

Serhud [2]3 years ago

3 0

Answer:

b + 5

Step-by-step explanation:

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8) 7(p-6)= 8p - 34<br> any chance i can get the steps on how to solve this?

yan [13]

Answer:

Step-by-step explanation:

7(p-6)=8p-34

Distribute 7 into the parentheses on the Left Hand Side of the equation

7p-42=8p-34

get p together, so minus 7p on both sides

7p-7p-42=8p-7p-34

7p and -7p cancel out on L.H.S

-42=p-34

isolate p by adding 34 to both sides

-42+34=p-34+34

-34 and postitive 34 cancel out on the R.H.S

p=-8

Hope this helps! :)

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3 years ago

The two figures have a scale of 3:1. What is the length of the corresponding side in the second figure?

zhuklara [117]

I will say it will be c

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3 years ago

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A long distance runner ran 4x4x4x4x4x4 miles last year. How many miles is this?

Archy [21]

Answer:

4096

Step-by-step explanation:

4x4x4x4x4x4=4^6

Group them to multiply to make it easier:

4x4=16

4x4=16

4x4=16

16x16x16=4096

honestly just plug it into a calculator

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3 years ago

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The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20

drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, $P=P_0e^{bt}$

where, $P_0$ and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

$9600=P_0e^{b\times 0}$

So, $P_0=9600$

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

$18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\$

$\ln(23/12}=6b \\\\$

$b = \frac{\ln{1.92}}{6} \\\\$

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

$P=9600 \times e^{0.109\times t}$

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

$P=9600 \times e^{0.109\times 15}=49243$

Hence, the population of the rabbit in 2009 is 49243.

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