Question

Factor 4x^2 + 1x – 13

Answer 1

Answer:

$(x - \frac{\sqrt{209} - 1}{8} )(x - \frac{-1 - \sqrt{209} }{8} )$

Step-by-step explanation:

FACTS TO KNOW BEFORE SOLVING :-

Quadratic Formula :-

Lets say , there's an equation ax² + bx + c.

$=> x = \frac{-b + \sqrt{b^2 - 4ac} }{2a} \: or \: \frac{-b - \sqrt{b^2 - 4ac} }{2a}$

SOLUTION :-

According to the question ,

• a (Coefficient of x²) = 4

• b (Coefficient of x) = 1

• c (constant) = -13

By using quadratic formula ,

$x = \frac{-1 + \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4} \: or \: \frac{-1 - \sqrt{1^2 - 4 \times 4 \times (-13)} }{2 \times 4}$

$=> x = \frac{-1 + \sqrt{209} }{8} \: or \: \frac{-1 - \sqrt{209} }{8}$

$=> (x - \frac{\sqrt{209} - 1}{8} ) \: and \: (x - \frac{-1 - \sqrt{209} }{8} )$ are the factors of 4x² + x - 13.