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dezoksy [38]
3 years ago
11

What is 247,039 rounded to the nearest thousand?​

Mathematics
2 answers:
denis-greek [22]3 years ago
4 0

The next GREATER thousand is 248,000 .

The next SMALLER thousand is 247,000 .

247,039 is closer to 247,000 than to 248,000 .

So the nearest thousand is <em>247,000</em> .

kvv77 [185]3 years ago
3 0

Answer:

247,000

Step-by-step explanation:

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Answer:

y=-4x+5

Step-by-step explanation:

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Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds, and is
swat32

Answer:

1/3

Step-by-step explanation:

Range of data set: 12 - 6 = 6

Given that there is a uniform distribution:

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P(7<x<8) = 1/6

P(8<x<9) = 1/6

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P(10<x<11) = 1/6

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3 0
4 years ago
17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II
maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

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Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

4 0
3 years ago
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Answer:

4.5 minutes

Step-by-step explanation:

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so then .75 times 6=

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3 years ago
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Example

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