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3 years ago

5-x=12 two step equations

Mathematics

2 answers:

Feliz [49]3 years ago

6 0

Answer: x = -7

5-x=12

-5. -5

-x=7

-x/-1=7/-1

x=-7

Hope this helps !

Lisa [10]3 years ago

3 0

Answer:

x=-7

Step-by-step explanation:

ur welcome

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Factor completely 12x4 + 6x3 + 18x2.

Semmy [17]

Answer:

B)3x^2 (4*x^2 + 2x + 6)

Step-by-step explanation:

Step 1: Find the Greatest common factor of the given expression.

12x^4 + 6x^3 + 18x^2

The above expression can be written as .

= 2*2*3*x^4 + 2*3*x^3 + 2*3*3*x^2

Here 3x^2 is prime factor

Step 2: Let's take out the 3 $x^{2}$ and write the remaining terms in the parenthesis.

= 3x^2 (2*2*x^2 + 2x + 2*3)

= 3x^2 (4x^2 + 2x + 6)

Therefore, the answer is B)3x^2 (4*x^2 + 2x + 6)

Thank you.

8 0

3 years ago

A class of 40 students has 11 students who ride the bus and 10 students who are in the band. Three of the students who ride the

Alexxandr [17]

The denominator is 40
10-3=7 (number of students in the band who do not ride the bus)
7/40=0.175
0.174*100=17.5% chance
Hope this helps!

8 0

3 years ago

1 /2 + 3/ 4 ÷ 1/3 –1( they are fractions)

marysya [2.9K]

Answer:

2 2/4

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

3 0

3 years ago

Write the resulting inequality.

erma4kov [3.2K]

Answer:

1. 2≤5

2. 2>1

Step-by-step explanation:

1. -5+7≤-2+7=2≤5

2. -6/-3> -3/-3 = 2>1

Hope this helps you.

3 0

3 years ago