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Anuta_ua [19.1K]
3 years ago
11

When a product fails to perform as warranted, this is called a) contractual liability. O b) product malfunction. c) malicious ma

nufacture. d) breach of warranty
Mathematics
1 answer:
9966 [12]3 years ago
7 0

Answer:

When a product fails to perform as warranted, this is called <u>breach of warranty. </u>

You might be interested in
Consider the isosceles triangle. left side (2x+8)units bottom of triangle (4x-10)units right side of triangle (2x+8) units Part
Blizzard [7]

Complete Question

Consider the isosceles triangle. left side (2z+8)units, bottom of triangle (4z-10)units, right side of triangle (2z+8) units Part A Which expression represents the perimeter of the triangle? a.(4z+16) units b.(6z−2)units c.(8z−16) units d.(8z+6) units

Answer:

d. (8z + 6) units

Step-by-step explanation:

The formula for the Perimeter of a Triangle is :Side A + Side B + Side C

Hence,

(2z + 8)units + (4z - 10) units + (2z + 8)units

= (2z + 8 + 4z - 10 + 2z + 8)units

Collect like terms

= 2z + 4z + 2z + 8 - 10 + 8

= 8z + 6 units

The expression that represents the perimeter of the triangle is (8z +6) units

3 0
2 years ago
the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width
dolphi86 [110]

Answer:

  • Length = 17 inches

  • Width = 12 inches

⠀

Step-by-step explanation:

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, <u>According to the Question :</u>

⠀

{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( 2x + 5  )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 58  - 10}}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 48}}}}

⠀

{\longrightarrow \qquad { {\sf{ x =  \dfrac{48}{4} }}}}

⠀

{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\:  \:  \bigstar

⠀

Therefore,

  • The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}

⠀

Therefore,

  • The length of the rectangle is 17 inches .

⠀

8 0
1 year ago
Read 2 more answers
Help me pleaseee i need good grades
Sonja [21]
I gotchu one second❤️❤️❤️
7 0
3 years ago
Read 2 more answers
{8x [1+(20-6)]}÷ 1/2=
IceJOKER [234]
You would do 20-6 which = 14. + 1 =15. times 8= 120 then divide that by 1/2 =  240 if you do 120 divided by .5 in a calculator thats what you get. i hope that helps you

7 0
3 years ago
Find the coordinates of the midpoint of the segment connecting points (-3,-6) and ( 2,5)
marin [14]
I solved it on paper so it's easier. 

But good luck ! :)

4 0
2 years ago
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