Answer:
64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
Step-by-step explanation:
Volume of cylinder = V
Radius of cylinder = r = 0.5 m
Height of the cylinder = 5 m
Volume of cylinder = 

Mass of gasoline = m
Density of gasoline = d = 

Work done to pump the gasoline out of the tank W
Acceleration due to gravity = g 
The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m


64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
Answer:

Step-by-step explanation:
I assume your equation to solve is

When we have a product of two factors equal to zero,

The solution is either A = 0 or B = 0.
In this case, this means that we can break the equation into two equations:

Solving the first one, we get:

For the second one, we rewrite it as:

And we see that this equation has two solutions:

Therefore, the three solutions are:

x=-2 is equal to -x=2
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Answer:
is c simple
Step-by-step explanation:
because it is ok is simple if you tick wet my brain XD
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.
Tell me if you need any clarification
PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds
Tell me if you need any clarification