Answer:the relative ages of the rocks exposed in the circle cliff area are given below.
1. older rocks are exposed in the center and younger rocks in the flanking flatirons.
2. younger rocks are exposed in the center and older rocks in the flanking flatirons.
Step-by-step explanation: this is because whenever older rocks are exposed in circle cliffs, exposure occur at the center while younger rocks will be exposed in the flanking flatirons at this time.
2. But when younger rocks are exposed in contrast to the older rocks, these younger rocks are exposed at the center while the older ones receive exposure at the flanking flatirons.
Note that both cases interchange, exposure of a particular rock occur at the center and the next category of rock receive theirs at flanking flatirons.
Answer: 63%
Step-by-step explanation:
First find the rate of loss that would cause the average rate of loss over the 10-year period equal to 38.0%.
Assume that rate is x.
38 = (36.2 + 29.0 + 46.2 + 37.5 + 40.9 + 40.0 + 32.6 + 40.5 + 40.1 + x) / 10
38 = (343 + x ) / 10
380 = 343 + x
x = 380 - 343
x = 37%
The survival rate is the opposite of the rate of loss which means that the survival rate is;
= 1 - rate of loss
= 1 - 37%
= 63%
t is the number of hours Lamar worked as a tutor
We know that he worked for 92 hours total, so he worked 92-t hours as a waiter.
So his earnings are: 7t + 8(92-t) = 736 -t dollars
This expression seems logical as if Lamar worked 0 hours as a tutor and 92 as a waiter his earnings would be 8*92 = 736
If he worked as a tutor for 92 hours it would be 7*92= 644
736-92= 644
So our expression seems to be working.
Answer:
The solution to the equation system given is:
- <u>x = 2</u>
- <u>y = -1</u>
Step-by-step explanation:
First, we must know the equations given:
- 2x + 3y = 1
- 3x + y = 5
Following Crammer's Rule, we have the matrix form:
![\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
Now we solve using the determinants:
![x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%5C%5C5%261%5Cend%7Barray%7D%5Cright%5D%7D%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D%20%7D%20%3D%5Cfrac%7B%281%2A1%29-%285%2A3%29%7D%7B%282%2A1%29-%283%2A3%29%7D%20%3D%20%5Cfrac%7B1-15%7D%7B2-9%7D%20%3D%5Cfrac%7B-14%7D%7B-7%7D%20%3D%202)
![y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D%7D%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D%20%7D%20%3D%5Cfrac%7B%282%2A5%29-%283%2A1%29%7D%7B%282%2A1%29-%283%2A3%29%7D%3D%5Cfrac%7B10-3%7D%7B2-9%7D%20%3D%5Cfrac%7B7%7D%7B-7%7D%3D-1)
Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:
- 2x + 3y = 1
- 2(2) + 3(-1)= 1
- 4 - 3 = 1
- 1 = 1
And, with the second equation:
- 3x + y = 5
- 3(2) + (-1) = 5
- 6 - 1 = 5
- 5 = 5
Answer:
D.The function is decreasing for all real values of x where x < 1.5
Step-by-step explanation:
The vertex is at x=1.5, so the function is decreasing on one side of that and increasing on the other. Any answer choice with some number other than 1.5 as the boundary of increasing/decreasing can be ignored.
Of course one descriptor (<em>increasing</em> or <em>decreasing</em>) is not applicable for any interval that includes the point where the slope changes sign.
The function is decreasing for all real values of x where x < 1.5.
