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Ksivusya [100]
3 years ago
7

The set of ordered pairs represents a function. Write a rule that represents the function.

Mathematics
1 answer:
maks197457 [2]3 years ago
5 0
Y=3x^3 is the awnser
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Help me please ..........................
attashe74 [19]

Step-by-step explanation:

3 0
3 years ago
Graph the system of equations. {4x+4y=16 x+6y=−6 Use the Line tool to graph the lines.
tatiyna

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

4x+4y=16 -----> equation A

x+6y=-6 -----> equation B

we know that

The solution of the system of equations is the intersection point both graphs

In this problem

The intersection point is (6,-2)

therefore

The solution is the point (6,-2)

using a graphing tool

see the attached figure

5 0
3 years ago
c) Your parents have been advised to save 5% of their income for your college education, which would include money for housing,
Gennadij [26K]
In one year they would have saved up $2447.40 for your education
convert 5% into a decimal then divide by 100.

Hope this helped :)
3 0
3 years ago
Read 2 more answers
Rewrite the expression 15(8 - 2) using the distributive property.
Charra [1.4K]

Answer:

9

Step-by-step explanation:

15(8-2)

15-(6)

9

4 0
3 years ago
Read 2 more answers
Show all work and reasoning
Natalija [7]
Split up the interval [2, 5] into n equally spaced subintervals, then consider the value of f(x) at the right endpoint of each subinterval.

The length of the interval is 5-2=3, so the length of each subinterval would be \dfrac3n. This means the first rectangle's height would be taken to be x^2 when x=2+\dfrac3n, so that the height is \left(2+\dfrac3n\right)^2, and its base would have length \dfrac{3k}n. So the area under x^2 over the first subinterval is \left(2+\dfrac3n\right)^2\dfrac3n.

Continuing in this fashion, the area under x^2 over the kth subinterval is approximated by \left(2+\dfrac{3k}n\right)^2\dfrac{3k}n, and so the Riemann approximation to the definite integral is

\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n

and its value is given exactly by taking n\to\infty. So the answer is D (and the value of the integral is exactly 39).
8 0
3 years ago
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