Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK. Please explain how to find out BK
2 answers:
Answer:
Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.
Given: △ABC, m∠B=90°
Find: AC and BK.
Short leg 90 degrees Long leg Hypotenuse
AB=12 90 BC=16 AC= ?
AK = ? 90 BK = ? AB=12
AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]
Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]
BK / 16 = AB / AC
BK / 16 = 12 / 20
BK = (3/5)16
BK = 48/5
another answer let see this
AB^2+BC^2=AC^2
12^2+16^2=AC^2
144+256=AC^2
400=AC^2
20=AC
# be careful#
Answer: BK = 9.6
Step-by-step explanation: The equation of the line AC is y = (-3/4)x + 12. The line perpendicular to AC and passing through point B is y = (4/3)x. The point of intersection between BK amd AC is (144/25, 192/25). Those are the side lengths. Use Pythagorean theorem to find the hypotenuse.
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Step-by-step explanation:
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