Who missed meeeeeeeeee also 2x+5y=30 . find y

Mathematics

1 answer:

VMariaS [17]3 years ago

8 0

Step-by-step explanation:

2x+5y=30

5y=30-2x.

$y = \frac{30 - 2x}{5}$

$y = \frac{2(15 - x)}{5}$

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Mrs Adams baked some muffins. Carl eat 2/5 of the muffins and John eat 25. How many muffins were baked?

Dennis_Churaev [7]

Answer:

Well, how many were left over? Mrs. Adams has a muffin factory and made 1 million muffins. Carl ate 2/5 or 40% or 400,000 muffins, and John ate 25. 599,975 muffins were shipped for sale. That meets the stated requirements.

Hence, we have to guess there were supposed to be no muffins left over.

In that case, Mrs. Adams baked 125/3 muffins, Carl ate 2/5 of them = 50/3, leaving 75/3 = 25 for John.

Step-by-step explanation:

x muffins baked, 2/5 eaten by Carl, 3/5 left to be eaten by John, who ate 25 before running out.

3/5 x = 25

x = 25 × 5/3 = 125/3 = 41 + 2/3

Or, Start with x muffins. Carl ate 2/5 x, leaving 3/5 x. John ate 25 with zero left over. So 3/5 x = 25.

(x - 2/5 x) - 25 = 0

3/5 x = 25

x = (5/3) × 25 = 125/3.

8 0

2 years ago

Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin

sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

$\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x$