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PIT_PIT [208]
3 years ago
6

An independent research firm conducted a study of 100 randomly selected children who were participating in a program advertised

to improve mathematics skills. The results showed no statistically significant improvement in mathematical skills, using a significance level of 0.05. The program is effective, which of the following would be an appropriate method for increasing power in this context?
a. Increase the sample size to 200 children.
b. Use a two-sided test instead of a one sided test.
c. Decrease the sample size.
d. Use alpha-0.01 instead of a-alpha.
e. Use a one sided test instead of a two-sided test.
Mathematics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

b) use a two-sided test instead of a one sided test.

Step-by-step explanation:

If we are using a significance level of 0.05, then the two-tailed test assigns half alpha to test for statistical significance in one direction and half alpha to test statistical significance in the other direction. This implies that .025 is present in each tail of the test statistical distribution. When using the two-tailed test, regardless of the direction of the relationship you assume, we test the possibility of the relationship in both directions.

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What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

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Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

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f(2n)/f(n)=2

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f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

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2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

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f(n)=2n

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f(2n)/f(n)=2(2n)/2n

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