Answer:
11) x = 21
12) x = 110
13) x = 85
14) x = 137
Step-by-step explanation:
Hope it helped <3
Option C
For each value of y, -2 is a solution of -21 = 6y - 9
<u>Solution:</u>
Given, equation is – 21 = 6y – 9
We have to find that whether given set of options can satisfy the above equation or not
Now, let us check one by one option
<em><u>Option A) </u></em>
Given option is -5
Let us substitute -5 in given equation
- 21 = 6(-5) – 9
- 21 = -30 – 9
- 21 = - 39
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option B)</u></em>
Given option is 3
- 21 = 6(3) – 9
- 21 = 18 – 9
- 21 = 9
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option C)</u></em>
Given option is -2
- 21 = 6(-2) – 9
- 21 = - 12 – 9
- 21 = - 21
L.H.S = R.H.S ⇒ yes a solution
<em><u>Option D)</u></em>
- 21 = 6(9) – 9
- 21 = 54 – 9
- 21 = 45
L.H.S ≠ R.H.S ⇒ not a solution
Hence, the solution for the given equation is – 2, so option c is correct
Answer:
16 males and 9 females
Step-by-step explanation:
To solve this we can use a system of equations.
Let's start by naming the number of females x.
The number of males would then be y.
<u>Using these variables, we can set up 2 equations using info provided:</u>
A french class has a total of 25 students, -> x+y=25
The number of males is 7 more than the number of females -> x+7=y
Use substitution to solve.
<u>From the second equation:</u>
x+7=y
Subtract 7 from both sides.
x=y-7
Substitute that into the first equation.
x+y=25
y-7+y=25
Combine like terms.
2y-7=25
Add 7 to both sides.
2y=32
Divide both sides by 2.
y=16
Substitute y=16 into equation 2.
x+7=y
x+7=16
Subtract 7 from both sides.
x=9
Therefore, there are 16 males and 9 females in the french class.
11183333.3/10^7 = 1.11x10^-7.
Answer:
no
Step-by-step explanation:
threr is no 9
