Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
Step-by-step explanation:
first term = a = 352
Common difference = d = second term - first term
= 345 - 352
= (-7)
nth term = a + (n-1)*d
43rd term = 352 + (43-1)*(-7)
= 352 + 42 *(-7)
= 352 - 294
= 58
Answer:
11.9
Step-by-step explanation:
I just know this off the top of my head
The real one is 11.18034
Answer:
like this?
Step-by-step explanation:
I think it is A 54 because I did it already and I got a 100
