I'd say the bottom answer is the best answer
Answer:
Scientific Method:
Step-by-step explanation:
Scientific method is the set of basic rules that must be followed for the production of knowledge that has the rigor of science, that is, it is a method used for research and verification of a certain content. For several authors, the scientific method is the logic applied to science.
i hope this
The statement (A), statement (B), statement (D) are correct because the equation is y = 437.9x + 439.4
<h3>What is the line of best fit?</h3>
A mathematical notion called the line of the best fit connects points spread throughout a graph. It's a type of linear regression that uses scatter data to figure out the best way to define the dots' relationship.
From the data given, we can calculate the correlation coefficient, slope of the line, and y-intercept.
r = 0.90
Since r is close to 1 shows a strong correlation.
Slope of the line of best fit = 437.9
Y-intercept of line of the best fit = 439.4(Refer to the attached picture)
The line will be:
y = 437.9x + 439.4
Thus, the statement (A), statement (B), statement (D) are correct because the equation is y = 437.9x + 439.4
Learn more about the line of best fit here:
brainly.com/question/14279419
#SPJ1
Question:
Consider ΔABC, whose vertices are A (2, 1), B (3, 3), and C (1, 6); let the line segment AC represent the base of the triangle.
(a) Find the equation of the line passing through B and perpendicular to the line AC
(b) Let the point of intersection of line AC with the line you found in part A be point D. Find the coordinates of point D.
Answer:


Step-by-step explanation:
Given




Solving (a): Line that passes through B, perpendicular to AC.
First, calculate the slope of AC

Where:
--- 
--- 
The slope is:



The slope of the line that passes through B is calculated as:
--- because it is perpendicular to AC.
So, we have:


The equation of the line is the calculated using:

Where:

--- 

So, we have:

Cross multiply




Make y the subject

Solving (b): Point of intersection between AC and 
First, calculate the equation of AC using:

Where:
--- 

So:



So, we have:
and 
Equate both to solve for x
i.e.


Collect like terms

Multiply through by 5

Collect like terms

Solve for x


Substitute
in 


Take LCM


Hence, the coordinates of D is:
