Answer:
0.8333 = 83.33% probability that the cycle time exceeds 50 minutes if it is known that the cycle time exceeds 45 minutes
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

Uniformly distributed over the interval 40 to 75 minutes.
This means that 
It is known that the cycle time exceeds 45 minutes
This means that we can use 
What is the probability that the cycle time exceeds 50 minutes?

0.8333 = 83.33% probability that the cycle time exceeds 50 minutes if it is known that the cycle time exceeds 45 minutes
Let's solve your equation step-by-step.<span><span><span>−w</span>+<span>4<span>(<span>w+3</span>)</span></span></span>=<span>−12</span></span>Step 1: Simplify both sides of the equation.<span><span><span>−w</span>+<span>4<span>(<span>w+3</span>)</span></span></span>=<span>−12</span></span><span>Simplify: (Show steps)</span><span><span><span>3w</span>+12</span>=<span>−12</span></span>Step 2: Subtract 12 from both sides.<span><span><span><span>3w</span>+12</span>−12</span>=<span><span>−12</span>−12</span></span><span><span>3w</span>=<span>−24</span></span>Step 3: Divide both sides by 3.<span><span><span>3w</span>3</span>=<span><span>−24</span>3</span></span><span>w=<span>−8</span></span>Answer:<span>w=<span>−<span>8</span></span></span>
Answer:
1/3
Step-by-step explanation:
I think not sure.
Answer:

Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
Data given
Confidence =0.99 or 99%
represent the significance level
n =16 represent the sample size
We don't know the population deviation 
Solution for the problem
For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:

We know that
so then
and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:
"=T.INV(0.005;15)" and we got
on this case since the distribution is symmetric we know that the other critical value is 