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3 years ago

The ratio 5:20 written as a fraction

Mathematics

2 answers:

iogann1982 [59]3 years ago

4 0

Answer:

1:4

hope helpful :) !!!!

saul85 [17]3 years ago

3 0

Answer:

5/20

Step-by-step explanation:

for every 5 lets say cookies there are 20 bottles of orange juice(Random)

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Select the correct answer. The area of a square is 9 square feet as shown below

kondaur [170]

The answer to the problem is A

6 0

3 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers

The rectangle is 16 inches by 25 inches. If the scale is 4 in :5 ft what is the length and width of the rectangle in feet.

Alenkasestr [34]

Answer:

The length and width of the rectangle are 20 feet and 31.25 feet, respectively.

Step-by-step explanation:

Let the scale be $4\,in\,:\,5\,ft$ and the dimensions of the rectangle being 4 inches and 5 inches, respectively. The scale ( $r$ ), measured in inches per feet, is equivalent to the following rational number: