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2 years ago

-) Amy bought a magazine for $4 and eight

Mathematics

2 answers:

Marianna [84]2 years ago

4 0

Answer:

she spent 5$ on each notepad

Step-by-step explanation:

magazine - 4$

8 notepads

40/8 = 5

MariettaO [177]2 years ago

3 0

Answer:

Step-by-step explanation:

(how much spent on notepads) 44 - 4 = 40

(how much for each notepad) 40 / 8 = 5

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Help asap please i don't know the answer lol

Sveta_85 [38]

Answer:

Step-by-step explanation:

The parallel line BC divides the sides AD and AE in proportion, that is

$\frac{AB}{BD}$ = $\frac{AC}{CE}$ , that is

$\frac{2}{3}$ = $\frac{AC}{4}$ ( cross- multiply )

3AC = 8 ( divide both sides by 3 )

AC = $\frac{8}{3}$ = 2 $\frac{2}{3}$ , hence

AE = AC + CE

= 2 $\frac{2}{3}$ + 4 = 6 $\frac{2}{3}$ → H

6 0

3 years ago

27.36 divided by 3.14 use compatible numbers to estimate the quotient

stiks02 [169]

Answer:

Step-by-step explanation:

you can round the numbers

27/3= 9

27.36 rounds down to 27 and 3.14 rounds to 3

6 0

3 years ago

Read 2 more answers

Translate (in terms of x) then solve the algebraic equation: The sum of a number and 3 is subtracted from 10 the result is 5.

vitfil [10]

Answer:

The answer is 2

Step-by-step explanation:

Let the number be x

10 - (3 + x) = 5

10 - 3 -x = 5

7 - x = 5

x = 7-5

x = 2

8 0

2 years ago

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0

2 years ago

Can yall help me out

Ainat [17]

Answer:

Option D, Yes, Devon should have evaluated f(3)

Step-by-step explanation:

f(x) = x^3 + x^2 − 10x + 8

<u>Step 1: Evaluate using F(3) NOT f(-3)</u>

f(3) = 3^3 + 3^2 - 10(3) + 8

f(3) = 27 + 9 - 30 + 8

f(3) = 14

Since the factor is (x - 3) the x value is x - 3 + 3 = 0 + 3 -> x = 3 not x = -3

Answer: Option D, Yes, Devon should have evaluated f(3)

6 0

3 years ago