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Ne4ueva [31]
3 years ago
9

A square is sometimes a rhombus

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

true

Step-by-step explanation:

a square is a rhombus because all sides are the same length but a rhombus is only a square when all the angles are 90°

Veseljchak [2.6K]3 years ago
4 0

Answer:

This would be true.

Step-by-step explanation:

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A five-digit number has the digits 0,9 7, 0, and 2. To the nearest thousand, it rounds to 30,000. What is the number?
arsen [322]

The answer could be 2970 or 2790


6 0
3 years ago
At sea world San Diego kid are only allowed into the air bounce if they are between 37 and 61 inches tall they are only allowed
ss7ja [257]

Answer:

Step-by-step explanation:

a. For the Air Bounce, children must be at least 37 inches tall. If we let h denote the child's height in inches, this means h≥37. They are also not allowed to be more than 61 inches tall so h≤61. We say h≥37 and h≤61. (This can be written as a compound inequality, but that is not expected at grade 6)  

For the Tide Pool Climb, children are not allowed to be over 39 inches. Using h for the child's height, this is represented by h≤39. We should also write this as 0<h since a height cannot be zero or negative.

b. The allowable heights in inches for Air Bounce are shaded blue on the number line below (note that they include 37 inches and 61 inches). No negative numbers are included on the number line as this does not make sense for the context of height.  

   

 

The allowable heights for Tide Pool Climb are shaded purple on the number line below:

   

 

Although it is not possible for a child to be close to 0 inches tall, these numbers are shaded because they fit the inequality h≤39. No negative numbers (or 0) are plotted because they do not make sense in the context of height. So the graph shows heights satisfying 0<h and h≤39.

c. In order go on the Tide Pool Climb, a child cannot be over 39 inches in height. In order to go on the Air Bounce, a child has to be at least 37 inches tall but not more than 61 inches. So to go on both, a child must be at least 37 inches tall but not more than 39 inches: 37≤h and h≤39. These heights in inches are highlighted on the number line below:

   

 

Notice that the shaded parts of this number line are where the shaded parts of the two previous underlines overlap: this makes sense as we are looking for heights of those who can go on both rides.

              ( I hope this helps and please Rate this answer it would really mean a lot to me :) )

6 0
4 years ago
determine The length of the circular arc of a circle with a radius of 49 cm subtended by a central angle of 135°
Katena32 [7]

Given:

Length of the circular arc with circle radius=49cm

θ=135°

Now,

Length of arc = θ/360°×2πr

49=2× 22/7×r×135°/360°

49×20×7/3×22×2

51.96cm

6 0
2 years ago
Find the area of this parallelogram
amid [387]

Answer:

98cm

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
in a square garden plot (with an area of 400 sq ft)deer fencing priced at $1.50 per foot is to be installed around the plot. if
mina [271]

We have a square garden of 400 square foot.

The area of a square is:

A=x^2

where x: side length.

In this case:

\begin{gathered} A=400=x^2 \\ x=\sqrt[]{400}=20\text{ ft} \end{gathered}

The perimeter of the square is the sum of the lengths of the sides of the square. As they are all equal, we can write:

P=4x=4\cdot20=80\text{ ft}

The fencing is priced at $1.50 per foot. If we add the 7% sales tax to this price we get:

C=1.50\cdot(1+0.07)=1.50\cdot1.07=1.605\text{ \$/ft}

The fencing will be installed in all the perimeter (80 ft).

We can calculate the total cost by multiplying the sales price ($1.605 per foot) and the perimeter (80 ft):

F=C\cdot P=1.605\frac{\text{\$}}{\text{ft}}\cdot80\text{ ft}=\$128.40

Answer: the fencing will cost a total of $128.40

8 0
1 year ago
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