Answer:
Step-by-step explanation:
We would use the t- distribution.
From the information given,
Mean, μ = 2950
Standard deviation, σ = 115
number of sample, n = 25
Degree of freedom, (df) = 25 - 1 = 24
Alpha level,α = (1 - confidence level)/2
α = (1 - 0.98)/2 = 0.01
We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01
The corresponding z score is 2.492
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
2950 ± 2.492 × 115/√25
= 2950 ± 2.492 × 23
= 2950 ± 57.316
The lower end of the confidence interval is 2950 - 57.316 =2892.68
The upper end of the confidence interval is 2950 + 57.316 = 3007.32
The solution is correct.
The answer is A.
You can get this by modeling the function. It's slope and y intercept will yield the equation y = -.5x +1.5. Then you can try the ordered pairs in that, all of which work.
THE ANSWER IS D whoops lol sorry i was in an argument lol
Answer:
4.80 mm to 2 d.p
Step-by-step explanation:
w = f(r)
f'(r) = (dw/dr) = (0.0218 mm/mm)
So, for a small difference in rainfall of 220 mm, what is the corresponding small difference in width of leaves in the two forests given.
One definition of a derivative or a rate of change is that it is the ratio of very small differences in the dependent variable to very small differences in the independent variable.
Mathematically,
(dw/dr) = (Δw/Δr) for very small Δw and Δr.
0.0218 = (Δw/220)
Δw = 0.0218 × 220 = 4.796 mm = 4.80 mm to 2 d.p
Hope this Helps!!!
Answer:
x = -7/4, 3
Step-by-step explanation:
Use quadratic formula
