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Zigmanuir [339]
3 years ago
14

Kyle is creating a frame for a model car. He begins by piecing two rods together, as shown in the diagram. Justify why AM = 6.

Mathematics
2 answers:
kiruha [24]3 years ago
6 0

Answer:

A Definition of Collinear Points

Great job you are correct. I also took the test and got it right.

Rama09 [41]3 years ago
4 0

Answer:

The correct choice here is <u>option A.</u> <em>Definition of Perpendicular Bisector</em>

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Marguerite is building a box. She needs 78 pieces of wood that are 29 cm long. The wood comes in boards that are 6 meters long.
ser-zykov [4K]
First, we are going to multiply the pieces of wood by the length of each piece to find the total length she will need:
78*29cm=2262cm

Next, we are going to convert 2262 centimeters to meters. To do that we are going to take advantage of the fact that 1 m=100cm:
2262cm* \frac{1m}{100cm} =22.62m

Now, we just need to divide the total length of wood Marguerite needs by the length of each board of wood:
\frac{22.62m}{6m} =3.77
Since she will need full boards of wood, we must round 3.77 to its nearest integer 4.

We can conclude that <span>Marguerite will need 4 boards of wood.</span>
7 0
4 years ago
Pls tell me how i should draw this
mezya [45]

Answer:

scale drawing you should use a limited unit of measurement so you are not drawing actual scale of the kitchen use 1 to40

8 0
3 years ago
5. Use a table of standard normal curve areas to find the following:
ANTONII [103]

Answer:

a. 0.7123

b. 0.1151

c. 0.0708

d. 0.6368

e. 0.7058

Step-by-step explanation:

  • the area to the right of z* can be stated as P(z<z*), and corresponding probability of z* on z-table gives the result.

a. The area to the left of z = 0.56 = P(z<0.56) = 0.7123

b. The area to the right of z = 1.20 =P(z>1.20)= 1- P(z<1.20)= 1-0,8849=0.1151

c. The area to the left of z = −1.47 = P(z<-1.47)= 0.0708

d. The area to the right of z = −0.35 =P(z>-0.35) = 1-P(z<-0.35)=1-0,3632=0.6368

e. P(-1.39<z<0.80) = P(z<0.80) - P(z<-1.39) = 0.7881-0.0823 = 0.7058

7 0
3 years ago
Find the measures of 1 and 2
juin [17]

Answer:

1 ) ∠1 = 105    ∠2 = 75

2) ∠1 = 50     ∠2 = 50

Step-by-step explanation:

4 0
3 years ago
Suppose that the lifetime of tv tubes are normally distributed with a standard deviation of 1.1 years. Suppose that exactly 20%
IrinaK [193]

Answer:

4.924 years

Step-by-step explanation:

Lets denote X the lifetime of a tv tube (In years). X has distribution N(\mu, 1.1) , with \mu unknown.

We know that P(X < 4) = 0.2. Using this data, we can find the value of \mu throught standarization.

Lets call Z = \frac{X - \mu}{1.1} the standarization of X. Z has distribution N(0,1), and its cummulative function, \phi is tabulated. The values of \phi can be found in the attached file.

P(X < 4) = P(\frac{X - \mu}{1.1} < \frac{4 - \mu}{1.1}) = P(Z < \frac{4 - \mu}{1.1}) = \phi(\frac{4 - \mu}{1.1}) = 0.2

The value q such that \phi (q) = 0.2 doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that \phi(-q) = 0.8 , hence -q must be equal to 0.84. Thus, q = -0.84

But this value of q should match with the number \frac{4 - \mu}{1.1} , so we have

\frac{4- \mu}{1.1} = -0.84

4 - \mu = 1.1 * (-0.84) = -0.924

\mu = 4 - (-0.924) = 4.924

Thus, the expected lifetime of TV tubes is 4.924 years.

I hope this works for you!

Download pdf
7 0
4 years ago
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