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Crazy boy [7]
3 years ago
9

What is the relationship between the measure of angle and the reflex measure of the angle

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0
The relationship between the measure of an angle and its reflex angle is their sum is 360 degrees
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Explain why should record a 1 in the tens column when you regroup in an addition problem
daser333 [38]
Well you only do that when you are in the ones place and you have to regroup a 1in the tens place if you go past 19 then you are going to have to regroup a 2
8 0
4 years ago
Use the pythagorean theorem to find the missing side. Round your answer to the nearest tenth
Monica [59]

Answer:

x=14.02

Step-by-step explanation:

Use b=\sqrt{c^2-a^2} to solve for the missing side in the triangle. You will get a rounded answer of 8.49. Then you multiply that by 2 and subtract that value from 31. Then that will be your answer.

5 0
2 years ago
I need help plzzzzzzzzzzzz. I need you guys to show work too
Softa [21]

Answer:

22

Step-by-step explanation:

<h2>—Math</h2>

√(x+3) –4 = 1

√(x+3) = 1 +4

√(x+3) = 5

x + 3 = 5²

x = 25 –3

x = 22

6 0
3 years ago
Sofia has four times as many dollars as her friend jessie has. together the two have $35. how much money do they each have?
garik1379 [7]
4J = s
J + s = J + 4j = 5j = 35

J = 7
s = 28
3 0
3 years ago
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
4 years ago
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