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lukranit [14]
3 years ago
6

Help please due today

Mathematics
2 answers:
Readme [11.4K]3 years ago
6 0
I’m pretty sure Scale drawings is the correct answer!
Sphinxa [80]3 years ago
3 0

Answer:

it is Scale Drawing

Step-by-step explanation:

Floor plans and maps are some examples of scale drawings.

You might be interested in
An isosceles triangle has an angle that measures 94º. Which other angles could be in that
Nataly [62]

Answer:

43°

Step-by-step explanation:

In a isosceles triangle, two angles HAVE to be equal.

This means that 94 can be one of the angles that are equal, or the angle that is not equal to another angle.

Let's start with the fact that 94 can be one of the angles that are equal. (Note: angles in a triangle add up to 180)

94+94+x=180

188+x=180

There is NOT a possible value for x in this situation, as you cannot have a negative value of an angle. Therefore we must try the other situation where 94 is the angle that is not equal to another angle.

x+x+94=180

2x+94=180

Subtract 94 from both sides

2x=86


Divide both sides by 2

x=43

Therefore the answer is 43°

4 0
2 years ago
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
Q7Which statement is incorrect for the graph of thefunction y = -5 cosGcos( 3 (x – 3)) +62The period is 4.The amplitude is 3.The
guajiro [1.7K]

The given function is,

y=-5\cos (\frac{\pi}{2}(x-3))+6

The graph can be drawn as,

The period will be distance between two consequetive maximas,

\text{Period}=1-(-3)=4

Thus, period is correct.

The amplitude can be determined as,

\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}

Thus, amplitue is incorrect.

The range is,

y\in\lbrack1,11\rbrack

Thus, the range is correct.

The midline is,

\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}

Thus, the midline is correct.

Thus, option (b) is the solution.

5 0
1 year ago
Please simplify the answer!
frutty [35]

Answer:

y = 9

Step-by-step explanation:

Given

4 + \frac{y}{3} = 7

Isolate the term in y by subtracting 4 from both sides

\frac{y}{3} = 3 ( multiply both sides by 3 )

y = 3 × 3 = 9

7 0
3 years ago
Help me can you help with the second part
lapo4ka [179]

Answer:

12 packages with 2 toothbrushes and 3 soaps each

Step-by-step explanation:

5 0
3 years ago
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