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2 years ago

117 over 200 as a percent

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

6 0

117 times 100 11700 then divide by 200 which is 58.5 %

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Is there any slope in this?

Angelina_Jolie [31]

Nope anyway marry Christmas

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2 years ago

22. The height of a triangle is 4 centimeters less than the base. Write a function that

torisob [31]

The function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

let the base of the triangle be x

Height of the triangle = x - 4

Area of triangle = 1/2 × base × height

Area = 1/2 × x × (x-4)

Area = 1/2 (x² - 4x)

Area = 1/2 x² - 2 x

We can also write it as a function:

y = 1/2 x² - 2 x

Domain = (3 , ∞)

Range = [0, ∞)

Since 3 is not included in the domain, base of the triangle cannot be 3 cm.

Therefore, the function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.

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1 year ago

As one of her chores staci must vacuum 1/2 of the house if she already has vacuumed 1/3 of her share tonight what part of the ho

bonufazy [111]

Given that S<span>taci must vacuum 1/2 of the house.

If she already has vacuumed 1/3 of her share tonight the part of the house she has vacumed is given by

$\frac{1}{3} \ of \ \frac{1}{2} = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6}$

Therefore, she has vacuumed 1/6 of the house.
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2 years ago

The heights of young women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Young men the same age have heights d

murzikaleks [220]

Answer: 10.703%

Step-by-step explanation:

Let minimum height of the tallest 25% of young women be M.

Let Q be the random variable which denotes the height of young women.

Therefore, Q – N(64,2.70)

Now, P(Q˂M) = 1-0.25

i.e. P[(Q-64)/2.7 ˂ (M-64)/2.7] = 0.75

I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches

Let R be the random variable denoting the height of young men

Therefore, R – N (69.3, 2.8)

i.e. (R-69.3)/2.8 – N(0,1)

therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]

this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033

From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%

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