Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Answer:
FALSE, (2, 9) is not a solution to the set of inequalities given.
Step-by-step explanation:
Simply replace x by 2 and y by 9 in the inequalities and see if the inequality is true or not:
irst inequality:
so thi inequality is verified as true since 9 is larger or equal than 8
Now the second inequality:
This is FALSE since 9 is larger than 4 (not smaller)
Therefore the answer to the question is FALSE, (2, 9) is not a solution to the set of inequalities given.
