Answer:
Step-by-step explanation:
here A(-3,-2)
-3 is x and -2 is y
so use this formula to find A'
p(x,y)=p'kx,ky)
here k is a scale factor which is 1/2
A(-3,-2)=A'(1/2*-3.1/2*-2)
A'(-3/2,-1)
prime (not composite) as it can only be divided by 1 and itself
Answer:
7 square units
Step-by-step explanation:
As with many geometry problems, there are several ways you can work this.
Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.
The applicable formulas are ...
area of a trapezoid: A = (1/2)(b1 +b2)h
area of a triangle: A = (1/2)bh
So, our areas are ...
AQRS = AWSQE - AWSR - AEQR
= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)
Factoring out 1/2, we have ...
= (1/2)((2+5)·4 -2·2 -5·2)
= (1/2)(28 -4 -10) = 7 . . . . square units
Answer:
NW = 15.6 cm
Step-by-step explanation:
If ΔLMN ~ ΔNWR then:
Find NW by using Pythagoras' Theorem:
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
Given:
- a = RN = 6 cm
- b = RW = 14.4 cm
- c = NW
Substituting the given values into the formula and solving for NW:
Answer:
Step-by-step explanation:
width = w
L = 5w - 6
w(5w - 6) = 18
5w^2 - 6w = 18
5w^2 - 6w - 18 = 0
Using the quadratic equation formula
x = 2.58997 and
x = -1.38997 This root cannot be. (No rectangle has a minus length.
w = 2.58997
L = 5*2.58997 - 6
L = 6.94985
w = 2.59
L = 6.95
