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3 years ago

What is the height of the box

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

7 0

Answer:

8 in

Step-by-step explanation:

since the box is the same length in all sides, it is a cube.

length, width and height are all the same.

the volume is 512 in³.

and the volume of a cube is length×width×height = side length³.

512 = length³

length = 8 = width = height

Read more on probability;

brainly.com/question/7965468

$SPJ1

8 0

2 years ago

What is the surface area of the prism?

cestrela7 [59]

Step 1: Find the area of the bases (triangles)

A = 1/2 * base * height

A = 1/2 * 16 * 6

A = 48

48 + 48 = 96

Area of the triangles = 96 cm^2

Step 2: Find the area of the sides (rectangles)

A = base * height

A1 = 16 * 12

A1 = 192

A2 = 10 * 12

A2 = 120

120 + 120 = 240

240 + 192 = 432 cm^2

Step 2: Add the areas together

96 + 432

528 cm^2

Hope this helps!! :)

5 0

3 years ago

Find the missing side length.<br> 12<br> 15

sashaice [31]

Answer:

you need to show the shape or somet or else I can't rlly help

7 0

2 years ago

Read 2 more answers

Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a

rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that $\sigma = 2$

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when $M = 0.5$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.5 = 1.96\frac{2}{\sqrt{n}}$

$0.5\sqrt{n} = 2*1.96$

Dividing both sides by 0.5

$\sqrt{n} = 4*1.96$

$(\sqrt{n})^2 = (4*1.96)^2$

$n = 61.5$

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0

3 years ago

Please help me somebody will

Svetach [21]

Answer:

66/54

Step-by-step explanation:

4 0

2 years ago