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3 years ago

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There are 30 students on the debate team and 20 students on the math team. Ten students are on both the math team and debate tea

m. What is the total number of students on either team?
A) 20
B) 30
C) 40
D) 50

1 answer:

Sauron [17]3 years ago

5 0

Answer:

The answer would be 40 because 30+20-10=40

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A triangle has vertices at L(2, 2), M(4,4), and N(1,6). The

pav-90 [236]

Answer:

The rule for the transformation is (x, y) + (-X, -Y)

The coordinates of L'are (-2,-2).

The coordinates of N' are (-1,-6)

Step-by-step explanation:

90 degree rotation from (x,y) results in (-x, y) and 180 degree results in (-x,-y)

The coordinates will change accordingly

L(2,2) will become L'(-2,-2)

M(4,4) will become M'(-4,-4)

and

N(1,6) will become N'(-1,-6)

So the correct statements are:

The rule for the transformation is (x, y) + (-X, -Y)

The coordinates of L'are (-2,-2).

The coordinates of N' are (-1,-6) ..

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3 years ago

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If line segments A and B are parallel, which of the following pairs of angles are not equal?

anyanavicka [17]

Answer:

C: ∠6 and ∠2

Step-by-step explanation:

Step 1:

∠6 = ∠9 S.S. Int. ∠'s (Same Side Interior ∠'s)

Step 2:

∠9 + ∠2 = 180° Sum of line

Step 3:

∠9 ≠ ∠2

Answer:

C: ∠6 and ∠2

Hope This Helps :)

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3 years ago

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Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes

lys-0071 [83]

Answer:

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 680 trials

r = number of success

p = probability of success which in our question is 0.55

So, it means X <em>~ </em> $Binom(n=680, p=0.55)$

<em><u>Now, we have to find the mean and standard deviation of the given binomial distribution.</u></em>

Mean of Binomial Distribution is given by;

E(X) = n $\times$ p

So, E(X) = 680 $\times$ 0.55 = 374

Standard deviation of Binomial Distribution is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{680 \times 0.55 \times (1-0.55)}$

= $\sqrt{680 \times 0.55 \times 0.45}$ = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

3 0

3 years ago

PLEASE HELP QUICK ITS TIMED

juin [17]

Answer:

9

Step-by-step explanation:

I think what they are asking is to subtract the 3 tokens from 21 tokens he already has giving us 18. and since it says "Twice the number of tokens" I'm assuming you divide 2 from 18 giving you 9 tokens.

5 0

3 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

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3 years ago