Answer: 2 sticks.
Step-by-step explanation:
Given statement: You need 3 sticks of butter for every 24 cookies you bake.
Using unitary method , the number of sticks of butter used to bake 1 cookie=![\dfrac{3}{24}=\dfrac{1}{8}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B24%7D%3D%5Cdfrac%7B1%7D%7B8%7D)
Then the number of sticks of butter used to bake 1 cookie=![\dfrac{1}{8}\times16=2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B8%7D%5Ctimes16%3D2)
Hence, the number of sticks of butter used to bake 16 cookies= 2
5 35/36, solving steps attached below
Answer:
-100
Step-by-step explanation: -10^2
Answer:
a) p=0.2
b) probability of passing is 0.01696
.
c) The expected value of correct questions is 1.2
Step-by-step explanation:
a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.
b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6
.
Recall that
In this case, the student passes if X is at least four correct questions, then
![P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696](https://tex.z-dn.net/?f=P%28X%5Cgeq%204%29%20%3D%20P%28X%3D4%29%2BP%28X%3D5%29%2BP%28X%3D6%29%3D%5Cbinom%7B6%7D%7B4%7D0.2%5E%7B4%7D%280.8%29%5E%7B6-4%7D%2B%5Cbinom%7B6%7D%7B5%7D0.2%5E%7B5%7D%280.8%29%5E%7B6-5%7D%2B%5Cbinom%7B6%7D%7B6%7D0.2%5E%7B6%7D%280.8%29%5E%7B6-6%7D%3D%200.01696%20)
c)The expected value of a binomial random variable with parameters n and p is
. IN our case, n=6 and p =0.2. Then the expected value of correct answers is ![6\cdot 0.2 = 1.2](https://tex.z-dn.net/?f=6%5Ccdot%200.2%20%3D%201.2)
Answer:
98 x 24 = 2352
2352 x 2400 = 5,644,800
2352 x (-48) = - 112,896
5,644,800 - 112,896 = 5,531,904
5,531,904 x 24 = 132,765,696
Step-by-step explanation: