Given that a circle is inscribed in a square. The side of the circle touches the side of the square which is the diameter. So the diameter of circle is 6cm, in order to find it's radius, you have to duvide it by 2 :

$radius = diameter \div 2$

$radius = 6 \div 2$

$radius = 3cm$

3 0

4 years ago

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Jack and three of his friends

3241004551 [841]

Answer:

Step-by-step explanation:

Just divide by 4

4 0

4 years ago

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Let hh be the set of all points in the second quadrant in the plane v=ℝ2v=r2. that is, h={(x,y)∣x≤0,y≥0}h={(x,y)∣x≤0,y≥0}. is hh

BaLLatris [955]

No, $H$ is not a subspace of $V$ . A simple counter-example to the contrary: let $h\in H$ with $h=(-1,0)$ . However, scaling by -1 gives the vector $-h=(1,0)$ and $-h\not\in H$ .

7 0

3 years ago