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Lady bird [3.3K]
3 years ago
14

Solve the following equation for x: 5x + 3y = 15.

Mathematics
1 answer:
Blizzard [7]3 years ago
7 0

Answer:

x = negative three fifthsy + 3

Step-by-step explanation:

5x + 3y = 15

Subtract 3y from both the sides,

5x = 15 - 3y

Divide by 5 on both sides,

x = -3y/5 + 15/5

x = -3y/5 + 3

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A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
Branliest offered<br> solve the proportion<br> 12/x=6/7<br> 6x/4=8/12<br> 7/x+13=4/12<br> y+5/y=10/8
Tju [1.3M]
12/x=6/7 answer: x=14
6x/4=8/12 answer x = 0.4444444444
7/x+13=4/12 answer x=8
y+5/y=10/8 answer y=20
6 0
3 years ago
Can anyone help me with this question?
poizon [28]

Answer:

45 and 13…......

Step-by-step explanation:

devide

6 0
3 years ago
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motikmotik

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Step-by-step explanation:

Step-by-step explanation:

5 0
3 years ago
Asa received scores of 72, 97, and 82 on her last three math tests. She needs a mean test score of 82 to qualify for the math te
Flauer [41]

Scores are {72, 97, 82, x} where x is the unknown fourth score

They add up to 72+97+82+x = x+251

Divide this sum over four because there are four scores we want to average out. We end up with (x+251)/4 = M where M is the mean. Asa wants the mean to be 82, so make M = 82.

We can replace M with 82 and solve for x like so

(x+251)/4 = M

(x+251)/4 = 82

x+251 = 4*82

x+251 = 328

x = 328-251

x = 77

Asa needs a score of 77 on the fourth test so that the mean of the four tests is 82. If she scores higher than 77 on the fourth test, then the mean will be larger than 82.

-----------------------------------

Depending on what your teacher is looking for, the first step is to establish your variable. So you would say "let x = fourth score". However, that seems too easy. So perhaps your teacher is looking for the equation (x+251)/4 = 82 or some variant of it.

5 0
4 years ago
Read 2 more answers
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