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3 years ago

A person who is at least 18 years old is considered an adult. Write an inequality that represents this situation

Mathematics

1 answer:

Fiesta28 [93]3 years ago

6 0

Answer:

$a \geq 18$

Step-by-step explanation:

The question concerns the use of inequalities in correct mathematical language.

When we have the condition "at least", it means something is greater than and equal; when we have the condition "at most", it is lesser than and equal.

In this case, we must use the former condition. Let's denote age with the letter a.

Then, the correct inequality is going to be:

$a \geq 18$

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If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

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$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
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\end{array}\to &1\\
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\end{cases}$

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\\\\\\
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\\\\\\
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Step-by-step explanation:

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2 years ago

Read 2 more answers

2.Solve the following quadratic equations<br> i. 9x^2 - 1/16<br> ii. 2h^2 - 3h - 27

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$ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\
\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}$

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3 years ago