Answer:
The classification of that same given problem is outlined in the following portion on the clarification.
Step-by-step explanation:
⇒ ![E[x]=\Sigma_{x=0}^{x} \ x \ f(x)](https://tex.z-dn.net/?f=E%5Bx%5D%3D%5CSigma_%7Bx%3D0%7D%5E%7Bx%7D%20%5C%20x%20%5C%20f%28x%29)
On putting the values, we get
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⇒ 
On taking L.C.M, we get
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⇒ 
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1...
Whether she wins she would receive $225 with even a 1/4 chance, then she will lose and maybe get $0 with such a 3/4 chance although if she takes a gamble anyway though she will either have to compensate $40 wp 1.
2...
She seems to want the capital to benefit or win.
So
y=ax^2+bx+c
(x,y)
sub the points and solve
(4.28,6.48)
6.48=a(4.28)^2+b(4.28)+c
(12.61,15.04)
15.04=a(12.61)^2+b(12.61)+c
well, for 3 variables, we need equations and therefor 3 points
maybe we are supposed to assume it starts at (0,0)
so then
0=a(0)^2+b(0)+c
0=c
so then
6.48=a(4.28)^2+b(4.28)
15.04=a(12.61)^2+b(12.61)
solve for a by subsitution
first equation, minut a(4.28)^2 from both sides
6.48-a(4.28)^2=b(4.28)
divide both sides by 4.28
(6.48/4.28)-4.28a=b
sub that for b in other equation
15.04=a(12.61)^2+b(12.61)
15.04=a(12.61)^2+((6.48/4.28)-4.28a)(12.61)
expand
15.04 =a(12.61)^2+(81.7128/4.28)-53.9708a
minus (81.7128/4.28) both sides
15.04-(81.7128/4.28)=a(12.61)^2-53.9708a
15.04-(81.7128/4.28)=a((12.61)^2-53.9708)
(15.04-(81.7128/4.28))/(((12.61)^2-53.9708))=a
that's the exact value of a
to find b, subsitute to get
(6.48/4.28)-4.28((15.04-(81.7128/4.28))/(((12.61)^2-53.9708)))=b
if we aprox
a≈-0.038573167896199
b≈1.6791118501845
so then the equation is
y=-0.038573167896199x²+1.6791118501845x
if asking for hours to miles (as it looks like in this case, x to y) it would be 1/53
Answer:
Molly can drive her car 112 miles on 4 gallons of gas and 182 miles on 6.5 gallons write an equation to show the relationship between the number of gallons she has and the number of miles she can drive and how many gallons she would need to drive 420 miles⊂⇄∪↓Ф
Step-by-step explanation:
