<span>Y(−3, 4) is the original
</span><span>(x, y) → (x − 2, y + 1) is the rule you're using
(-3, 4) </span>→ (-3 - 2, 4 + 1)
(-3, 4) → (-5, 5)
<span>Y'(–5, 5)</span>
The answer is 1 over 3(3.14)(5²)(8)
The volume of the cylinder (V1) is:
V1 = π · r² · h (r - radius, h - height)
The volume of the cone (V2) is:
V2 = 1/3 π · r² · h (r - radius, h - height)
It is given:
r = 5 feet
h = 8 feet
π = 3.14
Therefore, the volume of the cone is:
V2 = 1/3 · 3.14 · 5² · 8 which is the same as 1 over 3(3.14)(5²)(8).
A. Let x = cheese and
y = chocolate
2x + y = 25
x + y = 20
B. Subtract the second equation from the first.
2x + y = 25
-(x + y = 20)
-—————
x = 5
Plug 5 back in to the second equation and solve for y.
x + y = 20
5 + y = 20
Subtract 5 from both sides.
y = 15
5 cheese and 15 chocolate
Used elimination method because coefficients on the y values were both 1 so it was easy to subtract the equations and eliminate the y variable.
Answer: 
Step-by-step explanation:
Move all terms to one side.
Use the Quadratic Formula.
, 
Answer:
55
Step-by-step explanation:
5(3)^2+4(2.5)
5(9)+4(2.5)
45+10
55
