Answer:
A. d ≤ –7 or d > 8.
Step-by-step explanation:
Given : 2d + 3 ≤ –11 or 3d – 9 > 15.
To find : What are the solutions of the compound inequality .
Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.
For 2d + 3 ≤ –11
On subtracting both sides by 3
2d ≤ –11 - 3 .
2d ≤ –14.
On dividing both sides by 2 .
d ≤ –7.
For 3d – 9 > 15.
On adding both sides by 9.
3d > 15 + 9 .
3d > 24 .
On dividing both sides by 3 .
d > 8 .
So, A. d ≤ –7 or d > 8.
Therefore, A. d ≤ –7 or d > 8.
Sum is the result of adding so
12 + x, but i don't see it as a option.
Answer:
B.
Step-by-step explanation:
Took the test :}
Answer:
Step-by-step explanation:
3 consecutive integers....
1st integer = x
2nd integer = x + 1
3rd integer = x + 2
the product of 1st and 3rd is 5 greater then 5 times the 2nd...
x(x+2) = 5(x + 1) + 5
x^2 + 2x = 5x + 5 + 5
x^2 + 2x = 5x + 10
x^2 + 2x - 5x - 10 = 0
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x - 5 = 0 x + 2 = 0
x = 5 x = -2
so it will be : 5,6,and 7 or -2,-1, and 0
1/4 is one of the fractions
