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2 years ago

Helpppp!!!! ASAP !!!!!!!!!!! Nowwwwwww hellpppp!!!

Mathematics

1 answer:

FromTheMoon [43]2 years ago

7 0

1. The fractions shown are 3/4 and 6/8.
2. The multiplier is 2.
3. The fractions shown are 12/18 and 4/6
4. The divisor is 3.

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Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number

Gnoma [55]

Sum/difference:

Let

$x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}$

This means that

$3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}$

Now, assume that $x$ is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that $x$ was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

$x = -15\sqrt{8}$

if again we assume x to be rational, we have

$\sqrt{8} = -\dfrac{x}{15}$

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

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2 years ago

50a3 + 10a2

Lady_Fox [76]

$50a^3+10a^2\\\\50a^3=10\cdot5\cdot a^2\cdot a=10a^2\cdot5a\\\\50a^3+10a^2=10a^2\cdot5a+10a^2\cdot1=\huge\boxed{10a^2(5a+1)}\to\boxed{A}$

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3 years ago

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Write a word problem that would require you to use 5,621 divided by 23.

scoray [572]

Answer:

I have exactly 5,621 dominoes, and, including myself, 23 people to set them all up. How many dominoes will each person set up?

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3 years ago

It says to solve each proportion which I forgot how to do. Please help.

skelet666 [1.2K]

You have to divide denominator by numerator to find the constant of proportionality.

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2 years ago

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If the points at (-4, 3) and (2, 3) are reflected over the x-axis to create two new points, what shape can be formed by the four

Svetllana [295]

Answer:

Step-by-step explanation:

Let $(a,b)\in \mathbb{R}^{2}$ , a reflection over the x-axis consists in the following operation:

$(a,b) \rightarrow (a,-b)$

If we know that $X = (-4,3)$ and $Y = (2, 3)$ , then the points translated over the x-axis are $X' = (-4, -3)$ and $Y' = (2,-3)$ , respectively. The most precise description of the shape is a rectangle for the following facts: