Answer:
7.7 repeated
Step-by-step explanation:
3 1/3 * 2 1/3 = 7.7 repeated
Answer:
average atomic mass = 207.2172085 amu
Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.
For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)
The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu
Hope this helps :)
Answer: 50%
Step-by-step explanation:
There's a 50% chance of landing on tails. So, it would land on tails about 100 times.
Answer: next point would be (12,-6)
Step-by-step explanation:
rise over run
:))
Answer: correct trigonometric ratios
SinB, tanA and cos A.
Step-by-step explanation:
The right triangle has two sides 5 and 12 , by Pythagoras it's hypotenuse is 13.
Tan B=5/12,
Sin A =12/13
