I'm really confused, can someone please help me with this problem?

Analyze the pre-image ABCD. What are the vertices of the final image if T–1, –2 ◦ ry = x is applied to figure ABCD? A'' B''(3, 2

Katen [24]

No one will understand if you don't add the picture but the answer from Edgenuity is

A: (3,0)

B: (3,2)

C: (1,1)

D: (1,-1)

Your Welcome

3 0

2 years ago

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Consider an isosceles trapezoid rotated about an axis of symmetry that passes through the midpoint of the bases. the minor base

Ronch [10]

Based on the calculation, the perimeter of the horizontal cross-section is equal to 36.13 cm.

<h3>How to calculate the perimeter?</h3>

In this scenario, the resulting geometrical shape formed when the cut is made at the middle of the height of the trapezoid and then rotated is a circle.

<u>Given the following data:</u>

Minor base = 10 cm.

Major base = 13 cm.

From the middle, the diameter of this circle is given by:

D = 1/2 (10 + 13)

D = 11.5 cm.

Now, we can calculate the perimeter:

Perimeter = πD

Perimeter = 3.142 × 11.5

Perimeter = 36.13 cm.

Read more on trapezoid here: brainly.com/question/4758162

#SPJ1

3 0

1 year ago

What is mathematical equation?

Talja [164]

Answer:

A statement asserting the equality of two expressions, usually written as a linear array of symbols that are separated into left and right sides and joined by an equal sign.

Step-by-step explanation:

A statement asserting the equality of two expressions, usually written as a linear array of symbols that are separated into left and right sides and joined by an equal sign.

8 0

2 years ago

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Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have