Which equation has infinitely many solutions? a 12 + 4x = 6x + 10 - 2x
b 5x + 14 - 4x = 23 + x-9 c
c X + 9 -0.8x = 5.2x + 17-8
d 4x-2x = 20
<span>(5x^7 y^2)(-4x^4 y^5) =-20x^a y^b
</span><span>
solve this:
(5x^7 y^2)(-4x^4 y^5)
= -20 x^(7 + 4) y^(2 + 5)
= -20 x^11 y^7
answer
</span>A) a=11, b=7
Answer:
see explanation
Step-by-step explanation:
To determine which ordered pairs are solutions to the equation
Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.
(- 1, - 6)
3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution
(- 3, 3)
3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution
(11, 3)
3(11) - 4(3) = 33 - 12 = 21 = right side ← thus a solution
(7, 0)
3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution
The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation
Answer:
alllllllll
Step-by-step explanation:
In this question , we have to simplify the given ratio, which is
12xy:3x
First we have to see which factor is common in numerator and denominator,
We can write 12 as 3 times 4, that is
So the common factor is 3x.
In the next step, we cancel out 3x
And that's the required simplified form .
