Hello from MrBillDoesMath!
Answer:
27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Discussion:
Let f(t) - 9 sqrt(t) sin(t), then
y' = f(x^3) * d(x^3)/dx - f(sqrt(x)) * d(x^1/2)/dx
= (9 sqrt(x^3)sin(x^3)) * 3x^2 - (9 sqrt(x^1/2)sin(x^1/2)) * (1/2) x^-(1/2)
= 27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Hope I didn't make a "bozo" error differentiating things!
Thank you,
MrB
Answer: A
Step-by-step explanation: So, first of all, this is a linear graph, which is represented by the equation y = mx + b.
b = y-intercept. The y-intercept is the point in which the line crosses the y axis. Assuming this graph has units that go up by 1, the y- intercept for this line is 2, which eliminates choices B and C.
This graph is going down, which means it is negative, so the format should be -mx + b, which is answer choice A. Hope this helps! :)
ANSWER
The points (1,2) and (7,2) lie on the given curve.
EXPLANATION
The given parametric equations are:
and
We make t the subject in the first equation to obtain:
We substitute this into the second equation to get:
When x=1,
When x=2
When x=7,
Therefore the points (1,2) and (7,2) lie on the given curve.
4.
40-32 is equal to 8.
8=5x-2 is equal to 2.
8/2 is 4.