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allochka39001 [22]
1 year ago
7

How many two-digit numbers are there in which the tens digit is greater than the ones digit?

Mathematics
1 answer:
Dovator [93]1 year ago
7 0

there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

#SPJ1

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The lengths (in centimeters) of the opposite side pairs are 59 cm , 38 cm. Option C) is the correct answer.

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<u>step 1</u> :

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Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.

<u>step 2</u> :

The opposite sides are AB and CD respectively.

The another opposite sides are BC and AD respectively.

<u>step 3</u> :

If both pairs of opposite sides are congruent, then

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<u>step 4</u> :

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<u>step 5</u> :

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