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2 years ago

15

Find the product of 98 and 863

2 answers:

artcher [175]2 years ago

6 0

98 x 863 = ?
Answer is 84,574

Fantom [35]2 years ago

3 0

Hey there!

All you need to do to find the product of two or more numbers is multiply them together. You can do this by using a calculator or, if you're not able to use one yet, you can do manual multiplication.

Either way, you can multiply 98 and 863 to get:

98 × 863 = 84,574

Hope this helped you out! :-)

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Please show all work!! this is algebra.

Mnenie [13.5K]

Franco:
3x+2y=19
Caryl:
2x+4y=24

now use elimination

-2(3x+2y=19)
1(2x+4y=24)
=
-6x-4y=-38
2x+4y=24
add them together
which equals -4x=-14
divide both sides by -4
-4x/-4=-14/-4
x=7/2

we found x, so we subsitute it into the the original equation

3x+2y=19
3(7/2)2y=19
2y+21/2=19
-21/2 -21/2
2y=17/2
divide by 2 on both sides
2y/2= 17/2/2
y=17/4

so x= 7/2 and y= 17/4

8 0

1 year ago

X + 18 greater than or equals 26

cricket20 [7]

Answer:

x + 18 ≥ 26

Step-by-step explanation:

"greater than or equals": ≥

x + 18 ≥ 26 is your answer.

If you are trying to solve it so you isolate x, subtract 18 from both sides:

x + 18 (-18) ≥ 26 (-18)

x ≥ 26 - 18

x ≥ 8

x ≥ 8 is your answer.

~

5 0

2 years ago

Read 2 more answers

In the figure below, two secants are drawn to a circle from exterior point U. Suppose that UW=45, UZ=30, and UX=22.5. Find UY

Alex777 [14]

UY = 25

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3 0

2 years ago

Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7

Dima020 [189]

Answer:

The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ .

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

$\dfrac{\textrm factor of P}{\textrm factor Q}$ ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial , P = -7 , Q = 4

Now , $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$

I.e $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$ = $\frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }$

Or, The rational zero are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$

Hence The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ . Answer

7 0

3 years ago

Simple interest $1200 8% 2years

Gennadij [26K]

This is a screen shot of an online calculator called mathportal.com it shows the work used to find the answer to this question

Hope this helped and have an amazing day :)

-yO mAmA

5 0

3 years ago