AD || BC and BD is the transversal,
Therefore, angle DBC = angle ADB = 42° [alternate angles]
AD || BC and BD is the transversal,
angle BAD + angle ABD + angle DBC = 180° [co-interior angles]
or, 106°+ angle ABD + 42° = 180°
or, 148° + angle ABD = 180°
or, angle ABD = 180°-148° = 32°
Therefore, angle ABC = (32+42)° = 74°
AB||CD and BC is the transversal,
angle ABC + angle BCD = 180° [co-interior angles]
or, 72+2x+12 = 180
or, 84+2x = 180
or, 2x=180-84 = 96
or, x = 48
Answers: a)48°
b)42°
c)72°
