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leonid [27]
2 years ago
15

I need help on this question?​

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
8 0
Gvcffbbbbhhffdxc.Fs wf ye
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What is the measure of ∠HFG?<br> (See attachment)
madam [21]
92 degrees

Triangle= 180 degrees
180-60-28= 92

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7 0
3 years ago
-2(x-5)=6(2- 1/2x)<br><br> Please show your work. Distributive property, remove variable
schepotkina [342]

The solution of given equation is x=2

Further explanation:

In order to solve the given equation we have to isolate the variable x on one side of the equation. The process will involve distributive property and simplification.

Given:

-2(x-5)=6(2-\frac{1}{2}x)\\Apply\ distributive\ property\\-2x-2(-5)=(6)(2)-(6)(\frac{1}{2}x)\\-2x+10=12-\frac{6}{2}x\\-2x+10=12-3x\\-2x+3x=12-10\\x=2

The solution of given equation is x=2

Keywords: Linear Equation, Distributive property

Learn more about linear equations at:

  • brainly.com/question/10169676
  • brainly.com/question/10208427

#LearnwithBrainly

6 0
3 years ago
What two numbers add up to -20 and multiply to -1125
Oliga [24]
I don't have my calculator handy just now. But just looking at that problem, why don't you try +20 and -45 and see if they do the job.
8 0
2 years ago
WILL GIVE BRAINLIEST - What is the length of the hypotenuse of the base?<br> *Picture linked below*
Citrus2011 [14]

Answer:

4sqrt(2) cm

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + 4^2 = c^2

32 = c^2

sqrt(32) = c

c = 4sqrt(2)

6 0
2 years ago
Read 2 more answers
ANSWER THE QUESTIONS PLEASE IT IS ON BEARING
artcher [175]

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

8 0
2 years ago
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