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Anettt [7]
2 years ago
8

Find f(x)+g(x), given f(x)=x^2-8 and g(x)=-2-x^2

Mathematics
1 answer:
Gnoma [55]2 years ago
8 0

\left(x^2-8\right)+\left(-2-x^2\right)=-10

\left(x^2-8\right)+\left(-2-x^2\right)

=x^2-8-2-x^2

=x^2-x^2-8-2

=-8-2

=-10

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6 0
3 years ago
Plz help and give explaination of how to do it
professor190 [17]

Answer:

25% decreased by 60% is 10

Step-by-step explanation:

New value =

25 - Percentage decrease =

25 - (60% × 25) =

25 - 60% × 25 =

(1 - 60%) × 25 =

(100% - 60%) × 25 =

40% × 25 =

40 ÷ 100 × 25 =

40 × 25 ÷ 100 =

1,000 ÷ 100 = 10

hope this helps :)

7 0
2 years ago
Carol's starting pay for her summer job is $10.25 per hour. Carol earns exactly 3 raises this summer.
zlopas [31]
We know that
1) <span>Carol's starting pay for her summer job is $10.25 per hour
</span><span>Carol earn per hour=$10.25 per hour
</span><span>
2) </span><span>For the first rise, she receives a 50 cent-per-hour raise
10.25+0.50=10.75
</span>Carol earn per hour=$10.75 per hour

3) <span>For the second rise, she receives a 10% raise per hour
10.75*1.10=11.825
</span>Carol earn per hour=$11.825 per hour

4) <span>For the third rise, she receives another 50 cent-per-hour raise
11.825+0.50=12.325
</span>Carol earn per hour=$12.325 per hour

5) At the start of next summer. She will be given a 5% raise per hour based on her pay at the end of this summer. <span>
12.325*1.05=12.94125
</span>Carol will earn per hour=$12.94 per hour

the answer is
$12.94 per hour
4 0
3 years ago
Of the 2,598,960 different five-card hands possible from a deck of 52 playing cards, how many would contain all black cards.
kumpel [21]

Answer: 65,780

Step-by-step explanation:

When we select r things from n things , we use combinations and the number of ways to select r things = ^nC_r=\dfrac{n!}{(n-r)!r!}

Given : The total number of playing cards in a deck = 52

The number of different five-card hands possible from a deck = 2,598,960

In a deck , there are 26 black cards and 26 red cards.

The number of ways to select 5 cards from 26 cards = ^{26}C_{5}=\dfrac{26!}{(26-5)!5!}

=\dfrac{26\times25\times24\times23\times22\times21!}{21!(120)}=65780

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780

3 0
3 years ago
Struggling!!! Math help plss!!! ​
Lina20 [59]

Answer:

Step-by-step explanation:

3 0
3 years ago
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